一共有y1-y19共有19個輸出，有D1-D10共10個數(shù)據(jù)寄存器，D1-D10這10個數(shù)據(jù)寄存器中的值可以是1-19中的任意一個。比如，如果D1=1則Y1動作，
                                                                                                                                                                                                                                   如 果D1=2則Y2動作，
                                                                                                                                                                                                                                    如果D1=3則Y3動作。。等等，需要對D1-D10這10個數(shù)據(jù)

寄存器的值分別于1-19比較，共需要19*10=190次比較，這樣的話，程序太長，有可以簡化的嗎，哪位大神能指導一下嗎，麻煩了。跪求